Question

For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. kip ft B L/3 ft Lft COLLAPSE IMAGES w = 17 kipiift L = 9 ft The vertical reaction at support A. (Ay) kip ENTER 3 tries remaining. 1 point(3) possible The horizontal reaction at support A. (Ax) kip ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at support B. (By) kip ENTER 3 tries remaining. 1 point(s) possible The range for the equations across the beam. (0 <x< 0) ENTER 3 tries remaining. 1 point(s) possible The shear equation across the beam. kip ENTER 3 tries remaining. 1 point(3) possible The bending moment equation across the beam. kip.ft ENTER 3 tries remaining. 1 point(s) possible The internal shear force at C Kip ENTER 3 tries remaining. 1 point(s) possible The internal bending moment at C. kip.ft ENTER 3 tries remaining. 1 point(3) possible DENTUIG DRODI EM

Answer 1

Soin) 17 klp/ft Fe=0 - Ax = 0 9 Ft AX TAY By EMA=0 =) Efy=0 Ay+ By - 4x17x9 =0 Ayat = 76.5 kip By = 51 tip Ay By By49-(4***9) x 24 0 17x . 35.5 KIP tu ginie АА 125.5 Vr = 35.5 Lx 17 x 9 Vine = 25.5 - 17 ² 18 0< x <9th More 25.52 X 3 -15 17.). 25.5% - 1723 More - 54 shear force diagram Bending moment diggaam vikip Merip-fé) 88.33 kip-ft | 25.5 kip 3.804ft Ne B A А. + 50196 ft 5.196 3.804 -sikip X хз 17 kip 17 IB 35.5 = shear force at <> (6) 3 (Mc) - 15.5 X3 12 H54 B. M. at GB Kip-ft