Question

For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD.

w kip ft C A B L/3 ft L ftwhere w=23 kip/ft L=5 ft

find

The shear equation across the beam. kip ENTER X 2 tries remaining. 1 point(s) possible The bending moment equation across the

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Pox 23 kip) sign convention (+) (18+}19 m V VM А B * 512 By 케 k 54t 19.11 Parabolic (EMATO) By x5 - (*5*23)*(345) By = Ship B

Add a comment
Know the answer?
Add Answer to:
For the beam shown, draw the reactions at supports A and B in the positive direction,...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • For the beam shown, draw the reactions at supports A and B in the positive direction,...

    For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. kip ft B L/3 ft Lft COLLAPSE IMAGES w = 17 kipiift L = 9 ft The vertical reaction at support A. (Ay) kip ENTER 3 tries remaining. 1 point(3) possible The horizontal reaction at support A. (Ax) kip ENTER 3 tries remaining. 1 point(s) possible The vertical reaction...

  • For the beam shown, draw the reactions at supports A and B in the positive direction,...

    For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. Calculate w lb/ft PID Mb.ft с Lft B a ft bft COLLAPSE IMAGES w = 140 lb/ft P= 200 lb L = 7 ft a = 4 ft b = 4 ft M = 80 lb.ft The vertical reaction at A. (Ay) ID ENTER 3 tries remaining. 1 point(3)...

  • For the beam shown, draw the reactions at supports A and B in the positive direction,...

    For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...

  • For the beam shown, draw the reactions at supports A and B in the positive direction,...

    For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...

  • For the beam shown, draw the reactions at supports A and B in the positive direction,...

    For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. W lb A Lft Lft COLLAPSE IMAGES W = 248 lb L = 7 Calculate the vertical reaction (Ay) at support A ID ENTER 3 tries remaining. 1 point(3) possible Calculate the horizontal reaction (Ax) at support A ID ENTER 3 tries remaining, 1 point(s) possible Calculate the vertical...

  • For the beam show, calculate: w lb/ft p lb/ft L ft aft bft COLLAPSE IMAGES w...

    For the beam show, calculate: w lb/ft p lb/ft L ft aft bft COLLAPSE IMAGES w = 80 lb/ft p = 40 lb/ft L = 8 ft a = 8 ft b= 6 ft The vertical reaction at A. Іь ENTER 3 tries remaining. 1 point(3) possible The vertical reaction at B. lb ENTER 3 tries remaining. 1 point(3) possible The range for section 1. ) ft ENTER 3 tries remaining. 1 point(3) possible The shear force equation for section...

  • 1. (28 pts) A cantilever beam is subjected to the loads as shown in the figure....

    1. (28 pts) A cantilever beam is subjected to the loads as shown in the figure. Va) Draw a free-body diagram and determine the supports at point 0. b) Draw shear and moment diagrams and find the values at key points (i.e. x = 0, 6 and 10 ft). If possible, please show your calculations. c) Find shear force V(x) and bending moment M(x) for () <x<6 ft. 12 10 kip 2 kip/ft skip سے 40 kip.lt 611 4 11...

  • Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI...

    Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI bft Cross section EE COLLAPSE IMAGES W = 62 lb/ft W= 139 lb /y = 7 ft 12 =2 ft b = 0.5ft h = 0.1 ft M = 127 lb.ft int.com/#!/assessment/2015/247/Homework%2013 The vertical reaction at A. lb ENTER 3 tries remaining. 1 points) possible The horizontal reaction at A 1/1 pts 0 lb System Answer 0 The vertical reaction at B. lb ENTER...

  • Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section...

    Consider the beam below: w lb/ft Wlb h ft M lb-ft ---H --- bft Cross section EE li ft * COLLAPSE IMAGES W = 53 lb/ft = 148 lb ly = 8 ft 2 = 5 ft b = 0.5 ft h = 0.1 ft M= 143 lb.ft The vertical reaction at A. ENTER 3 tries remaining. 1 point(s) possible The horizontal reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at B. ENTER 3...

  • w lb/ft Wlb M Ib-ft hft b ft Cross section EE l, ft ft 2 W....

    w lb/ft Wlb M Ib-ft hft b ft Cross section EE l, ft ft 2 W. a m FourPoint Course The vertical reaction at B. b ENTER 3 tries remaining. 1 point's) possibie The range for section 1. ft ENTER 3 tries remaining. 1 pointis) possible The shear force equation for section 1 b ENTER 3 tries remaining. 1 pointis) possible The bending moment equation for section 1. b.ft ENTER 3 tries remaining. 1 poinns) possible The range for section...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT