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4. (20 points) Use z-transform to solve the difference equation y(k) -1.5y(k-1) + 0.56y(k-2) = x(k) for k> 0 with initial con

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here two conditions are taken 1.input is zero

2.initial conditions are zero

хск) - k2 uck) хск) Z+ transform XZ) back) Z 2-) K. UCK) - d 2 dz Kouck) دے Z (7-192. K. (kuck) E - 7 d 2 (2-1) d2 kluck) zcz

YC-1) = 3 Y1-2-4 Y? [-1.67-1+0,567-7 -1.583 + 2**3 702-11 +0.56*(-4) = ver-1.52-1 +0.56 4-2-4.5-3.2 443 444 1C+1) 4-113 Yc+)(

Y(2) z 23.92 ( 2018) 07.18 (-0.7) Y17) 23.92Z Z-0.8 17.182 (Z - 0.7) 23.92 1 I-0.82-1 17, 18 1-0.7ZY Yen) = 23.92(0.8) Puens

1.F2 = 0.8 1.44 Dco.23 (0) TD=1800 If t-0.7 1.19 = E[013]3[-0.1] E = 44 0.74 D compare coefficiens 24 term is zero A to A+D+E

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4. (20 points) Use z-transform to solve the difference equation y(k) -1.5y(k-1) + 0.56y(k-2) = x(k)...
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