Question

Find the equation of the line through 15,71 and perpendicular to the following equations a.y=7x+ The equation of the line in slepe interceptform is {Use integera or tractions for any numbers in the equation. b.y - 3x + 3 The equation of the line in slope-intercept form is ] (Usc inlegers or fractions for any numbers in the equation.) CX-2 The equation of the line in slope-intercept forms] (Use integers or fractions for any numbers in the equation. d. y = - 3 The equation of the line in slope-intercept form is (Use inlegers or fractions for any numbers in the equation.

Answer 1

to find equation of the line thorough (5,7) and peopendecuber to the following conations Y= 7x+6 The couetion of the line which is Pedipendecuber to y= 7*+6 and passes thorough point (5,7) m=slope perpendlecular to the line - -177 -1/7 y-Y,= m (2-4) y-7=/(0-5) 714-7) = -1 (0-5) 74-49 = -x+5 7y - X+5+49 -1+54 y = -x + 54

(6) y=-3x+3 slope = perpen decube to the line = V2 conation of line which is perpendecubr to the y=-3x+3 and passes through (5,7) yoy,= = m (2-x) y_7= Y(0-5) 34-21 = ans 3y y- X-5+21 x+16 2 +16 3 x = -2 - ma slope formation of line which is perpendecular to the X=-2 and passes thorough (5,7) y-y, = m(n-x) Y-7 = 0 (x - 5) y=7

ed, mz y = -3 slope oo in form of (y=0x-3) formation of line which is perpendecuber -3 and passes thorough (5,7) to y= gy,= m(aan, ) Y-7 = (0-5) (4-5) y = a-5 = =o X=5