Question

The monthly utility bill in a city is normally distributed. The mean is $120 and the standard deviation is $25. A utility bil
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Answer #1

a.

\small \\ P( X < 100) = P\left ( \frac{ X - \mu}{\sigma} < \frac{100 - 120}{25} \right ) \\\\ \\ P(X < 100) = P (z<-0.8) \\\\\\ P(X < 100) = 0.2119

Standardised value = -0.8

calculator command = normalcdf()

probability = 0.2119

b.

\small \\ P( 105<X < 125) = P\left ( \frac{105 - 120}{25} <\frac{ X - \mu}{\sigma} < \frac{125 - 120}{25} \right ) \\\\ \\ P( 105<X < 125)= P (-0.6 < z<0.2) \\\\ \\ P( 105<X < 125) = P(z < 0.2 ) - P(z < -0.6) \\\\ \\ P( 105<X < 125) = 0.5793 - 0.2743 \\\\\\ P( 105<X < 125) = 0.3050

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