Question

dynamics

Q1) A car was moving on a circular path of radius 54.8 m with a constant speed 21.92 m/s. Suddenly the driver starts to decrease the speed at a rate 1.371 m/s?. the acceleration just after braking is Select one: a. 0.00 b. 8.77 c. 9.86 d. 9.32 e. 11.23 the speed at t4s is Select one: a. 10.96 b. 5.70 c. 3.51 d. 19.51 e. 4.16 the acceleration at t=4s is Select one: a. 5.90 b. 14.87 c. 9.56 d. 13.69 e. 1.30 time to stop Select one: a. 9.16 b. 13.12 c. 1.24 d. 5.66 e. 14.26 the braking moved distance Select one: a. 82.67 b. 26.45 c. 42.99 d. 147.15 e. 31.41

Answer 1

just after braking - The acceleratu 22 R 21.922 64.8 = 8.768 rad/82 Tag = v-at, V₂ = Wi-atz 2 = 21.92- 1.37X1 = 20.55 - 1.3782 7 = 20.55 n 18 = 17.81 m/s 3 = V2 - atz - 17.81 1.3783 Vy = V₂ - at = 13-7-13784 8.22 m3 = 13.7m/s t=40 is 8.22 mis or speed at Accelerat" at t= 48 Vu au tu 8.22 = 2.05 m/s2 Time to stop V = vor at 0=21.92 - 1.37Xt t = 168 Braking distance, VW -08 0=21.922 _ 1.37 XS = 350.72 m