please, I need a right answres ASAP.
because one of the experts solved it wrong...
there is no wrong in the questions!!!!
not most of them are not in the choices !!!!!
1) b) 8.77 m/s^2
2) a) 10.96 m/s
3) a) 5.90 m/s^2
4) d) 5.66 s
5) a) 82.67 m
just after the braks are applied, total acceleration = radianl acceleration
a = v^2/r
= 21.92^2/54.8
= 8.77 m/s^2 <<<<<<<<-------------Answer
use, a = dv/dt
dv = a*dt
integral dv = integral a*dt
vf - vi = integral -1.37*t*dt
vf - 21.92 = -1.37*t^2/2
vf = 21.92 - 1.37*t^2/2
at t = 4 s
vf = 21.92 - 1.37*4^2/2
= 10.96 m/s <<<<<<<<-------------Answer
tangential acceleration, acceleration, a = -1.37*t
= -1.37*4
= -5.48 m/s^2
radial acceleration, a_rad = v^2/r
= 10.96^2/54.8
= 2.192 m/s^2
total acceleration, a = sqrt(a_tan^2 + a_rad^2)
= sqrt(5.48^2 + 2.192^2)
= 5.90 m/s^2 <<<<<<<<-------------Answer
when the car stops, vf = 0
use, vf = 21.92 - 1.37*t^2/2
0 = 21.92 - 1.37*t^2/2
==> t = 5.66 s <<<<<<<<-------------Answer
now use,
use, v = dx/dt
dx = v*dt
integral dx = integral v*dt
= integral (21.92 - 1.37*t^2/2)*dt
= 21.92*t - (1.37/2)*t^3/3
substitute t = 5.66 s
delta_x = 21.92*5.66 - (1.37/2)*5.66^3/3
= 82.67 m <<<<<<<<-------------Answer
please, I need a right answres ASAP. because one of the experts solved it wrong... there...
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