Question

The table below gives results from random samples of weights (in pounds) of men and women. Pop Gender 1 Men 2 Women n s 40 8.7 33 10.6 At a 0.05, test the claim that weights of men are more consistent than weights of women. 1. The alternate hypothesis is Ha: Osı > S2 O si <S2 Οσι < σ2 Oo > 02 2. This is a left tailed test with: df and dfa 3a. The STS (to 2 decimals) is F = 3b. The P-value (to 3 decimals) is: 4a. At a = 0.05, the decision is: O Accept Ho O Reject Ho O Do not reject Ho O Accept Ha 4b. The conclusion is: There is sufficient evidence to support the claim that weights of men are more consistent than weights of women There is sufficient evidence to reject the claim that weights of men are more consistent than weights of women There is insufficient evidence to support the claim that weights of men are more consistent than weights of women There is insufficient evidence to reject the claim that weights of men are more consistent than weights of women

Answer 1

Given that Pop Gender S men 40 8.7 Women 2 33 10.6 At d=0:05 we have to test the claim that Consi stenh > than men are more weights of weight of women Null hypothesis (Ho) : -9 (1) T < Alternative hy bothesis (Ha): (claim) This is lett -tailed tes with 6 dfon = 40-1 = 39 dfn=39 dfd 32 = 32 (3 a) The Sample test stabishic is s² 8.7? 75.69 10. 6² 112 36 0.676 si F = 0.670 7 cs Scanned with CamScanner

36) The P. value pis PEPCF < 0.67) 0.12 P=0.12 d=0.05 the decision is AL 4a) / not reject Ho evidence to support insufficient 46) There is the claim men ave that Weights of ot Women than weight more consistent CS Scanned with CamScanner