#include <stdio.h>
int main(int argc, char *argv[]) {
int i;
for (i = argc - 1; i > 0; i--)
printf("%s ", argv[i]);
printf("\n");
return 0;
}
can you explain this code in c and why use this function
Here is the answer for your question in C Programming Language
Kindly upvote if you find the answer helpful.
Explanation :
NOTE : I have used dev-c++ to execute this code, in this compiler we can pass arguments via parameters option. By default the first parameter will be the path of the file, and the parameters we pass will be displayed via this program.
CODE :
#include <stdio.h> /* It prints arguments from last to first as is starting
from last argument |
SCREENSHOTS :
Please see the screenshots of the code below for the indentations of the code.
Passing parameters in dev-c++
Parameters we pass here will be displayed by the program in reverse order of strings(Each word seperated by space is an argument)
OUTPUT :
Any doubts regarding this can be explained with pleasure :)
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