Question

how to find the reynold number and friction number?

Test section: Rough pipe Test section diameter: 0.0254m Area 5.067x10-4m2 Water temperature : 27°C Pipe Length : 1m Density at 27°C: 996.59 kg/m3 Dynamic viscosity at 27°C: 0.8509x10-3 Pas Theoretical value: Roughness: 0.0015 mm Flowrate, o (m^3/h) 1.4 Velocity(m/s) Reynold number, Re 0.767 Friction factor 1.2 0.658 1.0 0.548

Answer 1

Solution p = 996.59 kg / m² d=0.0254m, W=0.8509*10-3 kg msec Roughness (E) = 0.0015 mm Relative Roughess ( 0.0015 * 10-3 m 5.91*10-5 (Affook 0.02544 (1 V= 0.767 m/sec Re = Sud Shower 996-59 Wyhl * 0.7677hbec * 0.02549 u 0.8509*10-9 f basec = 22817.45 (Affron)

# We Know H -18& E 111, + 성 ||3·4 6. 9 Re com D 1 = -1.8 성 591 105 11-11 + 609 3.7 228 17:45 I = -1.8 ly (30714 * Lot)

1 f = 39.97773049 # f 0.658 m/sec Shower Chauer = 0.025014 Abhoog 0 VE # Re= 996-5999 m * 0.658m|pec* 0.025 hay 19575 Abhos 0.8509*10-7 ng see 1 -18 15.91*10 6.9 Wf 19575 from 17.11 t. 3.7 1 f 38.4982189043193 # f = 0.026 Alphone Gij) &= 0.548 m/sec Re = 996.59 91 * 0.54876/38€ * 0.0254) Ag lyngec Answer 0.8509*10-3 = 16302:43 Alboros from 1 =-1.8 y69 111 5.91*10-5 + 3.7 6.9 16302:43 1 / 2 = 36.76506542258714 Showersf = 0.0272 Alper If

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