Question

Home Task • Verify Maximum power transfer for circuit given below. • Do necessary calculations • Simulate circuit. 622 212 + 612 RL 10V

Note :-

1. Need Proper Calculations with relevant Explanation.

2. Simulation wil be Done on " FALSTAD".( falstad.com/circuit/circuitjs.html )

3. Your "Simulated" and "Calculated" values Should Same.

Answer 1

Solution: Verify the maximum power transfer. Consider the given circuit. The amount of power dissipated across the load resistor is, P1 = 1²R The circuit modified as follows: Rih + Rk 16

The current I is, Vih I= (1) Ron+R The power in the load resistor P, is, Th PZ V Rn+R R (2) The condition for maximum power transfer is, R = RM Modify the circuit as follows:

62 21 MAOA 1 1. + e VAR=VTb cov V B 7h = Calculate the voltage Von using Kirchhoff s current law. VI-10 V V + 0 622 62 2V 7 = 10 V V = 5V

To find the value of Rn. 6x6 +29 6x6 Rini = = 59 The condition for maximum power transfer is, R; = RM Substitute 592 for Ron: Rz = 502 Substitute 59 for Ron, 59 for Ry, and 5 V for Vin in equation (1). 5V 592+592 = 0.5 A

Substitute 512 for R, 592 for Ry, and 5 V for Vin in equation (2). P = 5 V 592 +592 (512) = 1.25 W Thus, the maximum power transfer is 1.25 W

Simulation: Circuit is simulated in FALSTAD using the link http://falstad.com/circuit/circuitjs.html and it is shown in below. 6 2 500 mA 6 5 2.5 V resistor I = 500 mA vd = 2.5 V R=50 P= 1.25 W

From the simulation, the current I is, I = 500 mA = 0.5 A And the power across the load resistor is, P2 = 1.25 W Therefore, the theoretical calculations are verified with the simulation results.