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In the figure there are two scenarios. On the left, block A and block B have a mass of mĄ and mg respectively with mA< MB. Th
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A A B Block-1 FBR Block 1 F Block-2 et २ YT Ati T2 A B с May meg (Ti-T2)&= - maty Los (mog - T): MAC (T-mag) = man (11 a= odputting in equolion (Ti-T2)2 = 2 [(TI-T2 ) = ma 2 - T = Tz + mca R putting the value of T, in ea Mag - Ma — -R+ mca 2 with 1now, • Considering the block 2 (sig) (F-T2)7: mensen (F-T2 ): mea 2 (Te-mag): mau adding above two equations F- mag - mc ce 2Hello dear pls see the process although I tried to avoid any calculation mistakes..pls let me know if there is any calculation mistakes...thanks..

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