Question

Will the results change if the pellets were heated for extra 10 minutes? Yes or No and explain the reasoning.

3 + 15 6 0.1651 g The initial mass of hydrated CuSO4.XH20 The final mass of anhydrous CuSO4 0.1055 g Mass of H2O in the hydrate 0.0596 g Moles of H, in the hydrate 3.3 x 10" moles Moles of the anhydrous salt CuSO4 6.6 x 10 moles Percent of water in the hydrate 36.1 % Number of H2O moles per mole of CuSO4 5 Calculations 6.2 Mass of H2O in the hydrate = 0.1651 -0.1055 = 0.0596 g 6.3 Moles of H, in the hydrate=0.0596/18=3.3 x 10 moles 6.4 Moles of the anhydrous salt Cuso, = 0.1055/160 = 6.6 x 10 moles 6.5 %=(0.16516) * 100% = 36.1 % 3.3 x 10 mol H, 6.6 H2O = 6.6 x10 CuSO = 5.0