i am using minitab to solve the problem.
steps:-
copy the data in minitab stat basic statistics 2 sample t select summarized data in sample 1 type 64 in sample size, 160 in sample mean, 20 in standard deviation in sample 2 type 36 in sample size, 140 in sample mean, 10 in standard deviation options in confidence level type 95 in hypothesized difference type 0 select the alternative hypothesis as difference > hypothesized difference ok ok.
*** SOLUTION***
hypothesis:-
[ i am denoting male by sample 1 and female by sample 2]
[ claim ]
the test statistic is (t) = 6.66
p value = 0.000
decision:-
p value = 0.000 < 0.05 (alpha)
we reject the null hypothesis. There is enough evidence to claim that average weight of male patients is more than that of female patients.
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QUESTION 23 4 points Problem 23) For a project that investigates the average weight difference by...
QUESTION 22 Problem 22) For a project that investigates the average weight difference by gender of patients from the Mayo clinic the researcher collected a sample of 64 male patients and another sample of 36 female patients. The researcher then calculated the sample mean of male patients as 160 lbs with a sample standard deviation of 20 lbs, and the sample mean of female patients as 140 lbs with a sample standard deviation of 10 lbs. Test the claim that...
Problem 20) For a project that investigates the average weight difference by gender of patients from the Mayo clinic, the researcher collected a sample of 64 male patients and another sample of 36 female patients. The researcher then calculated the sample mean of male patients as 160 lbs with a sample standard deviation of 20 lbs, and the sample mean of female patients as 140 lbs with a sample standard deviation of 10 lbs. Test the claim that the average...
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