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1. For the truss shown below pok IB 100 K E 20 ft F G 60 K 5@20f 1001 1. The truss shown is extemally (circle comect answer)

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#solution of PAGE-I Considering the conditions & plenetes & figure from the question 100 bile P / 100 20 क Kit By I G RF K *static équilibrin equations. • PAGE 2 {F 20 Katoro Ky=40 ie Ky=hol {fyzo Ky +P = 100+100-60 KytRf the EMK 20 140 x 20)+(220x7PAGE-3 Efyco / RAKO Joint ki 68 ARRB Jooks RKS tond - KJ AR two =26 T. 0-45 EF=0 RLB Cases + Rks = 40 fy -o Rizzsin 45 +6850PAGE-Y Efy -0. R257100-96.16 Postseo RBS 5-32 1 25 = 32(0) Joint. I - 32 R03 {fy=0 R 31+ legos 45=108 108 Rss {fy=o logginusPAGES {Fy=0 -101.82 sinus =RE - ROES -71-99 799(0) {fy=0 -101.82 cos 45 + REG + 100 Co. REC 3-28 = 27 ) * Joint G- ROG 28 10PAGE 6 RIH= 7811) Joint. I RI نا 7 RIS Rait R I HER I J = 76/7) Ro=0 PLEASE UPUOTE. -) *. *4 voy much necessely fois me

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