Question

ili Quot 12.3.14 Find the arc length parameter along the curve from the point where t = 0 by evaluating the integral s - Sivce)| dr. Then find the length of the indicated portion of the curve. -jwel de r(t)- (5 + 3)i + (4 +31)j + (2-7)k, - 1sts The arc length parameter is s(t)=0 (Type an exact answer, using radicals as needed.)

Answer 1

Given that re) ñ'TH = 3 + 3° -7ů (5+3+) { + (6 +3 +(+34)9+(2-76) K. -1'stlo t The length parameter is s(t) = J 1 vulde five o z - 11 (081(0)1147 51133,3,-2)1147 21410)+(-3)* de = √64t The length of the leugte of the indicated portion ="Surcesild Es (3,3,-711 dt ={V (31737 173 at - 9 -1 ✓ 67dt Toz [+] = 567 [ot] -1 =767

The arc length parameter is s(t) = 5674