Question

QUESTION 17 A manufacturing operation consists of a single machine tool system that produces an average of 15.5 transformer parts per hour. After undergoing a complete overhaul, the system was monitored by observing the number of parts produced in each of 17 randomly selected one hour periods. The sample mean - 15.42 and the sample standard deviation - 0,16 for the sample of ne17 production runs. Does the sample provide sufficient evidence to conclude that the true mean number of parts produced each hour by the overhaul is not equal to 15.57 True or false: The degree of freedom is 16. ОТ OF

Answer 1

Answer:

To test Ho: $1596168610431_blob.png$15.5 v/s H1:$1596168610441_blob.png$$\neq$ 15.5

Given that,

15.42 ,

T

Sample standard deviation=s=0.16

Sample size=n=17

Degree of freedom =n-1=17-1=16

Use $1596168610548_blob.png$0.05

# Test statistic,

11 t s/n

t=( (15.42- 15.5)/( 0.16/√17))

t= -2.0615

# Critical value:

At 95% confidence level, ctritical value for t test

tad.
= t_0.05,16=$1596168610457_blob.png$2.1199

Where $\left | t_{cal} \right |< t{_{critical}}$

We accept Ho

Conclusion :

At 5 % sighificance level, there is not enough evidence to conclude that the true mean number of parts produced each hour by the overhaul is not equal to 15.5