Question

x1 10 19 12 20 16 x2 21 16 13 19 13 20 19 x3 24 18 20 19 22 21 x4 19 20 16 25 x5 23 26 26 24 28 23 23 Test at a = 0.01 to determine if the population means are all the same. 1. The null hypothesis is Ho: Oui = 2 = 43 Oui = ly = H3 = 44 OM = H2 = H3 = HA = Hs 2. This is a right tailed test with: d.f.n = and d.f.d = 3a. The STS (to 2 decimals) is F = 3b. The P-value (to 3 decimals) is: 4a. At a = 0.01, the decision is: O Accept Ho O Reject Ho О Accept Ha O Do not reject Ho 4b. The conclusion is: There is insufficient evidence to conclude that not all means are equal There is sufficient evidence to conclude that not all means are equal There is sufficient evidence to conclude that all the means are equal There is insufficient evidence to conclude that all the means are equal Submit Question

Answer 1

using excel>data>data analysis>ANOVA

we have

Anova: Single Factor
SUMMARY
Groups	Count	Sum	Average	Variance
x1	5	77	15.4	18.8
x2	7	121	17.28571	10.90476
x3	6	124	20.66667	4.666667
x4	4	80	20	14
x5	7	173	24.71429	3.904762
ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Between Groups	314.7475	4	78.68686	8.23262	0.00025	4.218445
Within Groups	229.3905	24	9.557937
Total	544.1379	28

1 ) the null hypothesis is given by option C

2 ) df n = 4 and df d = 24

3 a) The STS = 314.748

3 b ) the p value is 0.000

4 ) Reject Ho   

4b ) option D is true