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Three ice cubes (55 g each) at 0.00 °C are dropped into 2.00 cups (kitchen measuring...

Three ice cubes (55 g each) at 0.00 °C are dropped into 2.00 cups (kitchen measuring cups) of tea. The tea was at room temperature (25.0 °C) before the ice was added. After the ice and tea have been mixed and thermal equilibrium has been established the temperature of the tea was 0.0 °C. How much ice remains floating in the tea?

Use these information to solve these questions: cp for tea or water is 4.184 J · g −1 · °C−1 , The energy required to melt ice = 333.6 J · g −1 (we should call it Hfus), This means it takes 333.6 J to melt 1.0 g ice. 1 cup = 236.6 mL

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