Homework Answers
Solution:
| Class (1) |
Frequency (f) (2) |
Mid value (x) (3) |
f⋅x (4)=(2)×(3) |
f⋅x2=(f⋅x)×(x) (5)=(4)×(3) |
| 0.5-3.5 | 6 | 2 | 12 | 24 |
| 3.5-6.5 | 5 | 5 | 25 | 125 |
| 6.5-9.5 | 4 | 8 | 32 | 256 |
| 9.5-12.5 | 5 | 11 | 55 | 605 |
| n=20 | ∑f⋅x=124 | ∑f⋅x2=1010 |
Sample Standard deviation S=√∑f⋅x2-(∑f⋅x)2nn-1
=√1010-(124)22/19
=√1010-768.8/19
=√241.2/19
=√12.6947
=3.563
Sample Standard deviation =3.56
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