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HC2H2O2 (aq) + NaOH(aq) + NaC2H2O2 (aq) + H2O(1) Trial Vi (mL) V (mL) 3.79 14.14...
Question 1 1 pts HC2H2O2 (aq) + NaOH(aq) - NaC2H302 (aq) + H2O(1) Trial V;(mL) V...
Question 1 1 pts HC2H2O2 (aq) + NaOH(aq) - NaC2H302 (aq) + H2O(1) Trial V;(mL) V (mL) 13.82 1 3.54 2 3 For their first trial, a student pipettes 5.00 mL of a vinegar solution into an Erlenmeyer flask. The student titrates the vinegar with standardized NaOH with a molarity of 0.229 M. The volume of titrant used was recorded in the table above. Calculate the molarity of the vinegar solution for this trial. Enter a number without units.
I MAINLY NEED HELP ON TABLES PLS HELP THANK YOU Materials: NaOH MW = 40 g/mL,...
I MAINLY NEED HELP ON TABLES
PLS HELP THANK YOU
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC2H4O4, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 mL water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the...
B. Determination of the Molarity of Unknown Acid Trial 1 Trial 2 Trial 3 Mass of...
B. Determination of the Molarity of Unknown Acid Trial 1 Trial 2 Trial 3 Mass of Erlenmeyer flask (g) 124 g Mass of Erlenmeyer flask+acid After adding 5 mL HCl solution (g) 135 g Mass of HCl solution (g) Mass of HCl solution (kg) -------- ------ -- Volume (acid), mL ----5mL------- -----5 mL--- ------5mL---- NaOH Initial Volume (Vi) 0.00 mL ------------mL -------------mL NaOH final Volume (VA) 16.5 mL ----------- -------------m L ml ---------mL NaOH Volume Used Vi-Vi --------mL L
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
3. A student pipetted 25.00 mL of a 0.2531 M solution of HCl into an Erlenmeyer...
3. A student pipetted 25.00 mL of a 0.2531 M solution of HCl into an Erlenmeyer flask. After adding 3 drops of phenolphthalein indicator to the flask, the student started adding NaOH from the burette, until the color in the Erlenmeyer flask turned light pink, The student calculated that 21.40 mL NaOH was transferred in the flask to neutralize the acid. a) Calculate the number of moles of HCl initially present (Reaction: NaOH(aq) + HCl(aq) -NaCl(aq) + H2O() b) Calculate...
4. Using the following reaction, H2SO4 (aq) + 2 NaOH (aq) → Na2SO4 (aq) + 2...
4. Using the following reaction, H2SO4 (aq) + 2 NaOH (aq) → Na2SO4 (aq) + 2 H2O () calculate the molarity of the H2SO4 solution if 17.45 mL of NaOH was necessary to reach the endpoint of a titration. The molarity of the NaOH solution was 0.425 M and 26.30 mL of H2SO4 was added to the Erlenmeyer flask.
A student titrates 25.00 mL of HCl(aq) with standard NaOH(aq) solution, requiring 33.72 mL of 0.2014...
A student titrates 25.00 mL of HCl(aq) with standard NaOH(aq) solution, requiring 33.72 mL of 0.2014 M NaOH to reach the end point. Calculate the molarity of the HCl(aq) solution.
1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used...
1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used in each trial = 0.20M 3. Volume of NaOH used in trail#1 (Final – Initial buret reading) = __17.80______ mL 4. Volume of NaOH used in trail#2 (Final – Initial buret reading) = ___18.20_____ mL 5. Average Volume of NaOH used = (#3 + #4) / 2 = ___18______ mL 6. Calculate Molarity of Acetic acid in vinegar = _________ M ?????? (molarity of...
Trial 6 Trial 5 Trial 2 Trial 4 Trial 3 Trial 1 Volume of acid sml...
Trial 6 Trial 5 Trial 2 Trial 4 Trial 3 Trial 1 Volume of acid sml solution acquired: smit smi smi 6 мм ISmI 1 omi omi omlomi Initial buret reading: OML Oml Final buret reading: umu 5ml smi u.sms . s u .s. *Volume of NaOH I UML solution used: smi I smi u.5ml 9.5 u.s. I volume trail m NaOH t (trail) 7 mol NaOH MGIHAI > MHCL *Molarity of acid solution: Name: *Average Molarity of acid: Percent...
Question 1 1 pts HC2H2O2 (aq) + NaOH(aq) - NaC2H302 (aq) + H2O(1) Trial V;(mL) V (mL) 13.82 1 3.54 2 3 For their first trial, a student pipettes 5.00 mL of a vinegar solution into an Erlenmeyer flask. The student titrates the vinegar with standardized NaOH with a molarity of 0.229 M. The volume of titrant used was recorded in the table above. Calculate the molarity of the vinegar solution for this trial. Enter a number without units.
I MAINLY NEED HELP ON TABLES
PLS HELP THANK YOU
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC2H4O4, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 mL water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the...
B. Determination of the Molarity of Unknown Acid Trial 1 Trial 2 Trial 3 Mass of Erlenmeyer flask (g) 124 g Mass of Erlenmeyer flask+acid After adding 5 mL HCl solution (g) 135 g Mass of HCl solution (g) Mass of HCl solution (kg) -------- ------ -- Volume (acid), mL ----5mL------- -----5 mL--- ------5mL---- NaOH Initial Volume (Vi) 0.00 mL ------------mL -------------mL NaOH final Volume (VA) 16.5 mL ----------- -------------m L ml ---------mL NaOH Volume Used Vi-Vi --------mL L
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
3. A student pipetted 25.00 mL of a 0.2531 M solution of HCl into an Erlenmeyer flask. After adding 3 drops of phenolphthalein indicator to the flask, the student started adding NaOH from the burette, until the color in the Erlenmeyer flask turned light pink, The student calculated that 21.40 mL NaOH was transferred in the flask to neutralize the acid. a) Calculate the number of moles of HCl initially present (Reaction: NaOH(aq) + HCl(aq) -NaCl(aq) + H2O() b) Calculate...
4. Using the following reaction, H2SO4 (aq) + 2 NaOH (aq) → Na2SO4 (aq) + 2 H2O () calculate the molarity of the H2SO4 solution if 17.45 mL of NaOH was necessary to reach the endpoint of a titration. The molarity of the NaOH solution was 0.425 M and 26.30 mL of H2SO4 was added to the Erlenmeyer flask.
A student titrates 25.00 mL of HCl(aq) with standard NaOH(aq) solution, requiring 33.72 mL of 0.2014 M NaOH to reach the end point. Calculate the molarity of the HCl(aq) solution.
Trial 6 Trial 5 Trial 2 Trial 4 Trial 3 Trial 1 Volume of acid sml solution acquired: smit smi smi 6 мм ISmI 1 omi omi omlomi Initial buret reading: OML Oml Final buret reading: umu 5ml smi u.sms . s u .s. *Volume of NaOH I UML solution used: smi I smi u.5ml 9.5 u.s. I volume trail m NaOH t (trail) 7 mol NaOH MGIHAI > MHCL *Molarity of acid solution: Name: *Average Molarity of acid: Percent...
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