Question

Using the Bonferroni method with a family confidence level of 95% and the ANOVA table below, answer the following questions: Source DF SS MS F-Value P.Value Industry 3 8.3605 2.7868 47.73 <0.0001 Gender 3 8.3069 2.768947.42 <0.0001 Interaction 90.2306 0.0256 0.44 0.9121 Error 144 8.4087 0.0583 Total 159 25.3067 Considering the table provided in the previous question, and to compare the treatment means (treatment combinations), what is the number of observations that comprise each treatment mean? 10 5 Assuming that the critical value associated with the Bonferroni approach is 3.61, then the value of the corresponding margin of error for comparing treatment combinations (rounded to two decimal places) is:

Answer 1

1) number of element in each treatment combination =(total df+1)/(industry(df)+1)*(gender(df)+1)

=(159+1)/((3+1)*(3+1))=10

2)

Margin of error =3.61*standard error =3.61*sqrt(0.0583)= 0.87