Question

can u solve it with all the steps and formulas used

tion Student Trun A company manufactures cylindrical planters. A town council wants planters with a wide rim for people to sit on. The company suggests that the area of the soil in the planter be about equal to the area of the rim. If the outer radius of the planter is 6.2 m, what is the radius of the soil? FOM 11 Select one: a. 4.4 m b. 1.8 m O c3.4 m X d. 3.8 m Solve 10x2 + 30% = 2x2 -30% - 75 by factoring. Select one: 30 13 MacBook Air

Answer 1

③ The The figure will be look like this. inner radius (radius) of soil Soil outen Rim radius Cleanly we can see that Area of the soil portions (en?) m? whene p = radius of the soil and Area of the larger circle = r *(6-2)2 where 6-2m=outen nadius :. Area of the Rim = m2 T (632) ro2 32 According to the question, Arica of the soil is about equal to Area of the Rim. r (6-2) ² rn2 r02 (6.252 222 -) 282 (6.232 22 ^ 38.44 2 TO yon √ 19:22 - 4.38 4.4m. Hence, nadius of the soil is 44m (approx)

2 3 we have 2 10x +30% = 201-302-15 2 1221²+600..+7520 =) 12x²+ (30+30) x +75=0 -) 1222 + 30x+300+7520 => băi (2x+5) +15 (21+5) = 0 (2x+5) (6x +15)= So, we get 21+5=0 on (62+15)=0 12-5 - 15 - - - - 2 Hence, nequined solution is i.e, org 22 x= -5/ -5 2

In the 1st problem, option (a) is correct. And in the 2nd problem, options are not given. If you have any doubt please comment.

Hope this will help you. Thank you.