We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
Question 3 9 pts The following reaction is taking place in a basic solution. Balance the...
The following reaction is taking place in a basic solution, Balance the equation using the half-reaction method (be sure and show work). How many hydroxides (OH) are there in the balanced equation? MnO4 (aq) +10, (aq) --> MnO2(aq) +10, (aq) 5 OH. on the reactant side 20H on the product side 20H-on the reactant side 20H- on the product side
Given the following skeletal half reaction in basic solution: MnO4 (aq) → MnO2(aq) electrons When the half-reaction is balanced in basic solution, are added to the side of the equation. O 5, product 3,reactant O 3, product O 5 reactant
Balance the following half-reaction occurring in basic solution MnO2(8) - Mn(OH)2(s) MnO2 (s) + H22(aq) + 2e - Mn(OH)2(s) MnO2(s) + 2H2O(l) + 26 - Mn(OH)2(s)+ 2OH(aq) MnO2(s) + 2H2O(l) - Mn(OH)2(3)+20H(aq) MnO2(s) + H2(g) - Mn(OH)2(s) + 2e- MnO2(s) + 2H2O(1) + 4e - Mn(OH)2(s)+ (OH)2 (aq)
Question 7 1.5 pts Given the partial equation: MnO4+1 MnO2+12, balance the reaction in basic solution using the half-reaction method and fill in the coefficients. The missing blanks represent H20, H, or OH, as required to balance the reaction. Enter the coefficients as integers, using the lowest whole numbers. If the coefficient for something is "1", make sure to type that in and not leave it blank. Enter only the coefficients. MnO4 + MnO2+
Balance the reaction between HPO32 and MnO2 to form Mno4- and H2PO2 in basic solution. When you have balanced the equation using the smallest integers possible, enter the coefficients of the species shown Water appears in the balanced equation as a (reactant, product, neither) with a coefficient of(Enter 0 for neither.) How many electrons are transferred in this reaction?
When the following oxidation–reduction reaction in basic solution is balanced, what is the lowest whole-number coefficient for OH–, and on which side of the balanced equation should it appear? Cr2O3(s) → Cr(OH)2(aq) + CrO42–(aq) a. 2, reactant side b. 10, product side c. 4, product side d. 4, reactant side e. 2, product side The answer is a, but I dont know how to get to the answer.
1. Consider the unbalanced redox reaction taking place in an acidic aqueous solution VO,* (aq) + S0,- (aq) → VO" (aq) + S0,- (aq) The unbalanced oxidative half-reaction for this redox reaction is: VO,* (aq) → VO" (aq) (la) Because the reaction takes place in aqueous solution, the reaction can be balanced by adding water. a. Add water to reaction (la) to balance the oxygen. This will give reaction (1b). (1b) Because the reaction takes place in an acidic solution,...
2. Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): MnO (s) + PbO2 (s) → MnO,- + Pb2+ (b) (acid solution): MnO4 + Mn2+ → MnO2 (s) (c) (basic solution): Al (8) + OH → Al(OH) - + H2(g)
Part A Balance the following equation by the half-reaction method. The reaction takes place in basic solution. Fe(s) + H2O(1) + O2(g) → Fe(OH)3(s) Express your answer as a chemical equation including phases. = AQ R O 2 ? 4Fe(OH)2 (s) + 2H, O(1) + O2 (g)+4Fe(OH)3 () Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining
Question 10 Even in basic solution, MnO, can oxidize water. One product is manganese(IV) oxide. Write a balanced chemical equation for the reaction Mnog (aq) + 6H20(1) - MnO2(5) + 2H2(g) + SOH(aq) 4Mno. (aq) + 2H,0(1) --- 4MnO (5) + 302(g) + 40H (ag) 4Mno. (aq) + H20(1) - 4MnO(s) + O2(g) +2014(aq) 2MnO4 (aq) + 2H20(1) --- 2Mn?"(aq) + 302(g) + 4OH(aq) Mno," (aq) +H:0(1) --- MnO (s) +H3(e) -OH(aq)