A processor of carrots cuts the green top of each carrot. washes the carrots, and insert six to a package. Twenty packages are inserted in a box for shipment. To test the mass of the boxes, a few were checked. The mean mass was 9.3kg. The standard deviation 0.16kg. How many boxes must the processor sample to be 95% confident that the sample mean does not differ from the population mean by more than 0.07kg?
Solution :
Z/2 = Z0.025 = 1.96
sample size = n = [Z/2* / E] 2
n = [1.96 *0.16 / 0.07 ]2
n = 20.07
Sample size = n = 21
A processor of carrots cuts the green top of each carrot. washes the carrots, and insert...
A processor of carrots cuts the green top off each carrot, washes the carrots, and inserts six to a package. Twenty packages are inserted in a box for shipment. To test the mass of the boxes, a few were checked. The mean mass was 9.2 kg, the standard deviation 0.17 kg. How many boxes must the processor sample to be 99% confident that the sample mean does not differ from the population mean by more than 0.13 kg? (Round the...
A processor of carrots cuts the green top off each carrot, washes the carrots, and inserts six to a package. Twenty packages are inserted in a box for shipment. To test the mass of the boxes, a few were checked. The mean mass was 9.2 kg, the standard deviation 0.17 kg. How many boxes must the processor sample to be 99% confident that the sample mean does not differ from the population mean by more than 0.13 kg? (Round the...
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