Would the outlier be 43.5 or 54? And same for would it 78 or 88.5? PART C
Sol)
Given data
62,65,57,64,57,54,64,62,65,57,58,57,59,56,78
Arranging in ascending order
55,56,57,57,57,57,58,59,62,62,64,64,65,65,78
n = 15
Median ( second quartile )
= ( n + 1 ) / 2 th term
= ( 15+1 ) / 2 th term
= 8th term
= 59
First quartile
Data before median
55,56,57,57,57,57,58
n = 7
First quartile = ( n + 1 ) / 2 th term
Q1 = ( 7 + 1 ) / 2 th term
Q1 = 4th term
= 57
Third quartile
Data after median
62,62,64,64,65,65,78
n = 7
Q3 = ( 7 + 1 ) / 2 th term
= 4th term
= 64
First quartile = 57
Second quartile = 59
Third quartile = 64
b )
Interquartile range
IQR = Q3 - Q1
= 64 - 57
= 7
Outliers
Q1 - 1.5 ( IQR )
57 - 1.5 ( 7 )
57 - 10.5
= 46.5
Q3 + 1.5 ( IQR )
64 + 1.5 ( 7 )
64 + 10.5
= 74.5
The values less than 46.5 and greater than 74.5 are considered as outliers
78 is the only value greater than 74.5
Option A
There exists at least one outlier in the data set is 78
Would the outlier be 43.5 or 54? And same for would it 78 or 88.5? PART...
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