1. Find Regression line equations from the following data
X | Y |
3 | 3 |
5 | 6 |
3 | 5 |
6 | 7 |
7 | 7 |
Solution:
x | y | x2 | y2 | x⋅y |
3 | 3 | 9 | 9 | 9 |
5 | 6 | 25 | 36 | 30 |
3 | 5 | 9 | 25 | 15 |
6 | 7 | 36 | 49 | 42 |
7 | 7 | 49 | 49 | 49 |
--- | --- | --- | --- | --- |
∑x=24 | ∑y=28 | ∑x2=128 | ∑y2=168 | ∑xy=145 |
Mean
ˉx=∑x / n
=24 /
5
=4.8
Mean
ˉy=∑y / n
=28 /
5
=5.6
byx={n∑xy-(∑x)(∑y)} / {n∑x^2-(∑x)^2}
={5⋅145-24⋅28}/{5⋅128-(24)^2}
={725-672}
/ {640-576}
=53 /
64
=0.8281
Regression
Line y on x
y-ˉy=byx (x-ˉx)
y-5.6=0.8281(x-4.8)
y-5.6=0.8281x-3.975
y=0.8281x-3.975+5.6
The regression equation is :
y= 0.8281 x + 1.625
when x=6 , y=0.8281*6+1.625 = 6.5936
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