Solution:
We have:
dfA = r - 1 = 2,
thus r = 2+1=3.
dfB = c - 1 = 1,
thus c = 1+1=2.
dfAXB = (r-1)*(c-1) = 1
dferror = r*c*(n-1) = 48
thus using
r*c*(n-1) = 48
3*2*(n-1) =48
6*(n-1) = 48
n-1 = 48/6
n-1= 8
n = 8+ 1
n = 9
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