Question

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2.1) — Solve. 21) An endangered species of fish has a population that is decreasing exponentially (A-Agekt). The population 6 years ago was 1600. Today, only 900 of the fish are alive. Once the population drops below 100, the situation will be irreversible. When will this happen, according to the model? (Round to the nearest whole year.) A) 23 years from today B) 22 years from today C) 25 years from today D) 24 years from today Solve the problem. 21) The function f(x) = 1 +15 In (x+1) models the average number of free-throws a basketball player can make consecutively during practice as a function of time, where x is the number of consecutive days the basketball player has practiced for two hours. After how many days of practice can the basketball player make an average of 9 consecutive free throws? A) 206 days B) 787 days 208 days D) 785 days Use common logarithms or natural logarithms and a calculator to evaluate to four decimal places 23) log 2 63.2 A) 0.7215 B) 2.8799 0.9993 D) 1.6686 23) 24) 25) Solve. 24) The value of a particular investment follows a pattern of exponential growth. In the year 2000, you invested money in a money market account. The value of your investment tyears after 2000 is given by the exponential growth model A =5100e0.057. How much did you initially invest in the account? A) $290.70 B) $2550.00 55100.00 D) $5399.14 Graph the inequality 25) y s-3x+3 Graph the function 26. Use the graph of f(x) = 5* to obtain the graph of gla) - 5* +

Answer 1

Kt A= Moe 22 1600. was 6 years ago only 900 of fish are alive Population Props below loo =) kt Aa Ao e K(-6) 1600 900 e 16 -6k e 9 16 = -6K -6K = In 1) -6k = 0.5753 K = -0.09589 Now As, Aa do okt Now As loo (-0.09589) t loo =900 e -0.09589 t et 11 e lufta -) -0.09589 t =

-0.09589 t -2.19722 t= 22.914 Soj 94 will 23 years Take Hence ofption A is True