Question

According to an airline, flights on a certain route are on time 75% of the time. Suppose 24 flights are randomly selected and the number of on-time flights is recorded. 

(a) Explain why this is a binomial experiment. 

(b) Find and interpret the probability that exactly 15 lights are on time 

(c) Find and interpret the probability that fewer than 15 flights are on time 

(d) Find and interpret the probability that at least 15 fights are on time. 

(e) Find and interpret the probability that between 13 and 15 flights, inclusive, are on time. 

(a) Identity the statements that explain why this is a binomial experiment Select all that apply. 

A. Each trial depends on the previous trial 

B. The experiment is performed a foved number of times 

C. The experiment is performed until a desired number of successes is reached 

D. There are two mutually exclusive outcomes, success or failure. 

E. The trials are independent 

F. The probability of success is the same for each trial of the experiment 

G. There are three mutually exclusive possibly outcomes, arriving on-time, arriving early, and arriving late 

(b) The probability that exactly 15 flights are on time is _______ (Round to four decimal places as needed)

 Interpret the probability 

in 100 trials of this experiment, it is expected about _______  to exactly than 15 fights being on time

(c) The probability that fewer than 15 flights are on time is _______ (Round to four decimal places as needed.) 

Interpret the probability 

in 100 trials of this experiment, it is expected about _______ to result in fewer than 15 fights being on time 

(d) The probability that at least 15 fights are on time is _______ (Round to four decimal places as needed) 

Interpret the probability 

in 100 trials of this experiment, it is expected about _______ to result in at least 15 nights being on time

Answer 1

hii... although I am trying to provide the detailed answer but if you have any doubt please ask by comment. please like the answer. thanks...

given n = 24 p=0.75 fixed DJ There are two mutually failure =1 X ₂ Bir in, pa PCX=21)= ( pcr-box=0, I,.. n. The expeziment is performed a fired number of times. exclusive outcomes, success of The trials are independent. The probability of success is the same for each toal of the experiment. E 24-15 b) PCX=15 (24) 10.75) (-0.75 0.0667 to In 100 trials of this experiment, it is expected about a renelt 19 a 24-21 c) PLX c.) 5 = E (24) 10.757 11-0.751 10.0547 In 100 bicus 5 d) PCX 2153= 1-PCXC/5) = 1-0547 = 10.9453 In 100 trial about 95