Total number of sample space when rolling two dice at random= n(S)= 6*6=36
Let E be the event that the sum of number on dice is 12
So, E={6,6}
So, Number of event that the sum of number on dice is 12 = n(E)= n[{1,2}]=1
So, probability that sum of number appearing on dice is 12= P( E)= n(E)/n(S)= 1/36=0.0278
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