Two dice are rolled repeatedly until the sum of the two numbers rolled is 10 or more.
a) What is the probability that exactly 5 rolls are needed? (Count each time you roll the dice as one roll).
b) What is the probability that more than 5 rolls are needed?
c) Find the expected number of rolls.
a)
here P(sum is 10 or more on pair of dice) =(P(10)+P(!1)+P(12)=(3/36)+(2/36)+(1/36) =6/36 =1/6
P( exactly 5 rolls are needed) =P(in first 4 rolls sum is less than 10 and on 5th 10 or more)
=(1-1/6)4*(1/6)=625/7776
b)
probability that more than 5 rolls are needed =P(first 5 roll all are below 10)=(5/6)6 =3125/7776
c)
expected number of rolls =1/p=1/(1/6)=6
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