Roll 10 dice. Find probability sum of dice is 42. (dice are 6-sided. Min roll =...

Question

Question

Roll 10 dice. Find probability sum of dice is 42.

(dice are 6-sided. Min roll = 10. Max roll = 120.)
(number of possible rolls = 6^10 = 60466176) = s^n

number of favorable rolls = number of ways dice add to 42

[(number of favorable rolls)/(number of possible rolls)] = [Probability sum is 42]

You must find number of favorable rolls.
Given number of dice(n), sides(s), and sum of roll (r) as
n = 10, s = 6, and r = 42.

What is the formula for for number of favorable rolls.

Answer 1

Answer #1

Answer 2

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