Question

5) A specific drive through receives 3 customers every 30 minutes on average. (a) What is the expected value of customers for them in an hour? (b) What is the probability that they receive exactly 5 customers in the next 90 minutes? (c) What is the chance that they do not receive any customers in the next 60 minutes? (d) What is the probability that they receives exactly 5 customers in the next 30 minutes?

Answer 1

X! Sol". If &~ Poisson (2) then P(X= 4) = eit at X=0,1,2,1 Given: d= 3 customess per 30 minutes (a) Expected value of customers for them in an hour fi.e.60 minutes) ď 2x3 = 6 Ang d=3x3 customers per go minutes ie. da And P(X=5) = 0-0607 51 P(x=0) = et (6) (c) a= 2x3 customers per bo minutes 0 (d) 2 = 3 customers per 30 minutes ce. = 3 P(x=5) e é 3 (3) 0.1008 And 51 e95 = 0.0025 Any - i.e. d -6 / نم