Question

QUESTION 34 4 points Save Answer A sample of size 45 will be drawn from a population with mean 94 and standard deviation 14. Find the 32nd percentile of the sample mean . 98.48 94.67 87.42 93.02 QUESTION 35 4 points Save Answer Construct a 95% confidence interval for the unknown population proportion, based on the given values of x and n: x= 78, n= 142 and fill in the blanks. We are confident that the population mean is between and 5%, 0.467, 0.631 95%, 0.467, 0.631 5%, 0.481, 0.618 95%, 0.480, 0.618

Answer 1

34 n=45, Ñ = 94, S = 14 We need to find, c such that, -0.4687 P (X<C) 0.32 C-94 $460:32) 14/145 (From Table) → c= (-0.468) 14 +94 = 93.02 145 Answer: 93.02

|35Foo 95% confidence , 2 =1.645 X =78n=142 Х 78 0-54929 = 0.5493 n 142 9 = 1-0.5493= 0.4507 elp = 0.5493, Opz 0.5493 * 0.4507 142 0.04 175 Maegin of extot = ME= zop= 1.645 X 0.04175 0.06868 confidence interval: CP-ME, P+ME) (0.5493-0.06868,0.549370106868) → (0.48062, 0.61798) C0.480,0.618) We ate 95% confident that the population propoetion Ps between 10.4802 and 10.618 je. 95%9 0.480 , 0.618