Question

Question 19 Not yet answered Points out of 7.00 p Flag question A hollow cylindrical conductor of inner radius a = 9 cm, and outer radius b = 22.5 has a non- uniform current density J = r2 in units of A/m². a . . (a) Calculate the magnetic field at distance r = 13.5 cm from the center of the conductor. Select one: • a. 501.03 E-ZT . b. 219.45 E-ZT . c. 13640.60 E-7 T

Answer 1

We know that given that a= gun b=22.5cm Current density alb J=x2 magnetic field at 8 = 13.5 cm & Bode Bode = lo Iene la Jodă so 5. da BETO) = 6 fra 27ody = id27) fråde das anody B(278)= l. 21 2012 la r=13.San a=gam B = He เY = 47X107 ک. B2Ar = ulan) (4) forte de 1 13.5jt glo Jx1224 41 13.5473) B = ya 710 13 l (3.3) 9 ge] B = 6.2026 Tiolo I to which is the r=13-5 Ciri amagnetic field at r= 27cm fB.de - »]5.dä = soffarda) ya Bos क the magnetic field at

b B(210) Il lio 27 7 ) j3dr 879 b B(210) = ومر = Mo 27 Mil7y(). (52 BP * () (ut x= 346m) B = (477107) |(22.5)-94 Jtljezje Y B ( 274702] (4) 29.057700 T E magnetic field at 8= 27cm the direction of magnetic field at point is →
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