Solution:
Class boundaries: The lower class boundry is found by subtracting 0.5 units from the lower class limit and the upper class boundry is found by adding 0.5 units to the upper class limit.
Class | frequency | class boundaries |
8-18 | 9 | 7.5-18.5 |
19-29 | 3 | 18.5-29.5 |
30-40 | 5 | 29.5-40.5 |
41-51 | 10 | 40.5-51.5 |
52-62 | 6 | 51.5-62.5 |
Hours Students Spend on Homework in a Week Class Frequency 8-18 9 19-29 3 30-40 5...
Consider the following frequency table representing the distribution of hours students watch tv in a week. Hours Students Watch TV in a Week Class Frequency 15 9-15 16-22 6 23-29 30-36 7 37-43 8 Copy Data Step 2 of 2: Determine the upper class boundary for the first class.
Consider the following frequency table representing the distribution of hours students spend on homework in a week. Hours Students Spend on Homework in a Week Class Frequency 7–13 13 14–20 14 21–27 12 28–34 7 35–41 4 Step 1 of 2 : Determine the relative frequency for the third class as a simplified fraction.
Consider the following frequency table representing the distribution of hours students spend on homework in a week. Class Frequency 13-21 11 22-30 9 31-39 3 40-48 3 49-57 15 Step 1 of 2: Determine the relative frequency for the fifth class as a simplified fraction. Step 2 of 2: Determine the relative frequency for the third class as a simplified fraction.
Consider the following frequency table representing the distribution of hours students spend on homework in a week. Determine the lower class boundary for the fourth class
For the following frequency distribution, what is the cumulative frequency for the class “30-under 40”? Class interval Frequency 10-under 20 20 20-under 30 16 30-under 40 30 40-under 50 18 20 36 66 30 83 2. 57 23 35 18 35 26 51 47 29 21 46 43 29 23 39 26 41 19 36 28 31 42 52 29 18 28 46 33 28 20 Class Interval Frequencies 16 - under 23 23 - under 30 30 - under...
can you please explain how you got the answers 1. Consider the following frequency table representing the distribution of hours students watch TV in a week. Week Hours Students Match Class Frequency 12- 19 20- 27 28-35 36- 43 44- 51 110 Step 1. Enter the lower class limit for the first class. Step 2. Enter the upper class limit for the second class. 19 2. Consider the following frequency table representing the distribution of cost of lunch in dollars)....
Previous Problem List (I point) Consider the following frequency distribution. Next Class Frequency 8-19 19-30 7 30-41 8 41-52 6 2 What is the midpoint of the first class? To the nearest hundredth, what is the relative frequency of the third class? 24 Note: You can earn partial credit on this problem. (Give a decimal number not a percentage,) You have attempted this problem 0 times. You have unlimited attempts remaining.
Based on the frequency distribution above, is 19 a: Please, anyone, help me and please explain step by step the solution :D Ages Number of students 15-18 19-22 23-26 27-30 31-34 35-38 4 8 6 3 Based on the frequency distribution above, is 19 a: Class midpoint Class width Class boundary Upper class limit Lower class limit
A professor had students keep track of their social interactions for a week. The number of social interactions over the week is shown in the following grouped frequency distribution. What is the class width? Number of Social InteractionsFrequencies5-10611-161817-221023-281329-341635-40941-46547-52653-58059-644
can you upload the answer in excel 7. Following are ages of 30 students in an ARC Boot Camp class: 18 30 20 21 28 26 20 21 19 22 26 38 18 19 23 25 19 20 18 21 29 35 17 22 19 24 23 21 20 25 Construct an expanded stem-and-leaf display for the given data. Stem Leaves 2. The following data values are the actual low temperatures recorded near the author's home. Construct a frequency distribution...