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[7 marks] Consider two independent populations. We took two SRS of sizes 10 from each population and x1 = 525.751, 52 = 107.1
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Sample Size Sample mean Sample S.D Sample 1 X1 = 525.751 52 = 107.121 Sample 2 X2=373.269 sz = 67.498 ni = 10 n2 = 10 The tes

P(t <3.808 ) = 0.9991 [using Excel function T.DIST(3.808,15,TRUE)] P-value = P(t> 3.808 ) = 1-P(t<3.808) = 1-0.9991 = 0.0009

That is , there is enough evidence to reject the null hypothesis.

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