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4. [7 marks] Consider two independent populations. We took two SRS of sizes 10 from each population and x1 = 525.751, $ı = 10
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Answer #1

Solution:

The test statistic t is given by

t = T1 T2 + ) 111 112

where   S denotes the pooled variance.

Therefore ,

t = 11 - 12 (nı-1)s+(12-1)s ni+n2-2 om + 11 n2

= 525.751 - 373.269 (10-10107.1212 + (10-1067.498211 10-10-2 10 (+

= 3.808

Test statistic t = 3.808

d.f. = n1 + n2 - 2 = 10 + 10 - 2 = 18

> sign in Ha indicates that " One tailed right sided test"

\alpha = 1% = 0.01

For right tailed test , critical value is tads +0.01.18 = 2.552

Test statistic t = 3.808 > 2.552

So , Reject H0

Yes , there is enough evidence to reject the null hypothesis

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