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A researcher wishes to estimate the proportion of adults who have high-speed Internet access. What size sample should be obta

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Answer #1

Solution :

Given that,

(a)

\hat p = 0.54

1 - \hat p = 1 - 0.54 = 0.46

margin of error = E = 0.04

Z\alpha/2 = 2.576

sample size = n = (Z\alpha / 2 / E )2 * \hat p * (1 - \hat p )

= (2.576 / 0.04)2 * 0.54 * 0.46

= 1030

sample size = n = 1030

(b)

\hat p = 1 - \hat p = 0.5

margin of error = E = 0.04

Z\alpha/2 = 2.576

sample size = n = (Z\alpha / 2 / E )2 * \hat p * (1 - \hat p )

= (2.576 / 0.04)2 * 0.5 * 0.5

= 1037

sample size = n = 1037

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