Consider the electric field due to q1 is E1, E1 makes an angle
1 with x-axis.
E1 = kq1/(r1)2 cos1
+ kq1/(r1)2 sin1
Where k = 1/4o,
r1 = SQRT[32 + 42] = 5 cm = 5 x
10-2 m
cos1
= 3/5, sin1
= 4/5
E1 = {[(9 x 109) x (22 x 10-9)] / (5 x
10-2)2} x 3/5
+ {[(9 x 109) x (22 x 10-9)] / (5 x
10-2)2} x 4/5
= 4.752 x 104
+ 6.34 x 104
-------------------------------------------------------------------------------------------------------------------
Consider the electric field due to q2 is E2, E2 makes an angle
2 with negative x-axis.
E2 = kq2/(r2)2 cos2
- kq2/(r2)2 sin2
Where k = 1/4o,
r2 = SQRT[22 + 42] = 4.47 cm = 4.47 x
10-2 m
cos2
= 4/4.47, sin2
= 2/4.47
E2 = {[(9 x 109) x (4 x 10-9)] / (4.47 x
10-2)2} x 4/4.47
+ {[(9 x 109) x (4 x 10-9)] / (4.47 x
10-2)2} x 2/4.47
= 1.61 x 104
- 0.805 x 104
-----------------------------------------------------
Net electric field, E = E1 + E2
= [4.75 x 104
+ 6.34 x 104]
+ [1.61 x 104
- 0.81 x 104]
= 6.36 x 104
+ 5.53 x 104
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