sample mean, xbar = 85.8
sample standard deviation, σ = 15.07
sample size, n = 64
Given CI level is 90%, hence α = 1 - 0.9 = 0.1
α/2 = 0.1/2 = 0.05, Zc = Z(α/2) = 1.64
ME = zc * σ/sqrt(n)
ME = 1.64 * 15.07/sqrt(64)
ME = 3.09
CI = (xbar - Zc * s/sqrt(n) , xbar + Zc * s/sqrt(n))
CI = (85.8 - 1.64 * 15.07/sqrt(64) , 85.8 + 1.64 *
15.07/sqrt(64))
CI = (82.71 , 88.89)
sample mean, xbar = 85.8
sample standard deviation, σ = 15.07
sample size, n = 64
Given CI level is 95%, hence α = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96
ME = zc * σ/sqrt(n)
ME = 1.96 * 15.07/sqrt(64)
ME = 3.69
CI = (xbar - Zc * s/sqrt(n) , xbar + Zc * s/sqrt(n))
CI = (85.8 - 1.96 * 15.07/sqrt(64) , 85.8 + 1.96 *
15.07/sqrt(64))
CI = (82.11 , 89.49)
The 95% confidence interval is wider
Optionn B) is interpretation
You are given the sample mean and the population standard deviation. Use this information to construct...
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