In a random sample of males, it was found that
24
write with their left hands and
207
do not. In a random sample of females, it was found that
57
write with their left hands and
465
do not. Use a
0.05
significance level to test the claim that the rate of left-handedness among males is less than that among females.
Identify the test statistic.
z=
(Round to two decimal places as needed.)
Identify the P-value.
P-value=
(Round to three decimal places as needed.)
To Test :-
H0 :- P1 = P2
H1 :- P1 < P2
p̂1 = 24 / 231 = 0.1039
p̂2 = 57 / 522 = 0.1092
Test Statistic :-
Z = ( p̂1 - p̂2 ) / √(p̂ * q̂ * (1/n1 + 1/n2) ) )
p̂ is the pooled estimate of the proportion P
p̂ = ( x1 + x2) / ( n1 + n2)
p̂ = ( 24 + 57 ) / ( 231 + 522 )
p̂ = 0.1076
q̂ = 1 - p̂ = 0.8924
Z = ( 0.1039 - 0.1092) / √( 0.1076 * 0.8924 * (1/231 + 1/522)
)
Z = -0.22
P value = P ( Z < -0.22 ) = 0.414
In a random sample of males, it was found that 24 write with their left hands...
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