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A simple random sample of front-seat occupants involved in car crashes is obtained. Among 2736 occupants not wearing seat bel

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Answer #1

Ho: P1 = P2 H: P1 > P2

b = = 39 == 0.0143 2736

Ô2 = x = 7198 = 0.0024

P= X1+X Ni+N2 39+19 2736+7798 0.0055

test statistic value is

PI -P2 p(1-D (1/nı +1/n2) 0.0143 -0.0024 0.0055 - (1 -0.0055) (1/2736 + 1/7798) = 7.187

p value is

P(Z>7.187) = 1-P(Z<=7.187) = 1-1 = 0.000

less than,Reject,is

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