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HF(aq) reacts with NaOH(aq) according to the reaction represented below. HF(aq) + OH(aq) - H2O(l) +...
What are the spectator ions in the reaction HF(aq) + NaOH(aq) - NaF(aq) + H2O(1) A.H* B.F C. Nat D. OH
Given: 1) NaOH Na+(aq) + OH- (aq) 2) NaOH + H+ Cl-(aq) H2O(l) + Na+(aq) + Cl-(aq) 3) Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) H2O(l) + Na+(aq) + Cl-(aq) Show that equations 1 and 3 can be added algebraically to give equation 2. We were unable to transcribe this imageWe were unable to transcribe this imageWe were unable to transcribe this image
Answer the following for the reaction: NiCl2(aq)+2NaOH(aq)→Ni(OH)2(s)+2NaCl(aq) A.) How many milliliters of 0.200M NaOH solution are needed to react with 48.0 mL of a 0.240 M NiCl2 solution? Express your answer with the appropriate units. B.) How many grams of Ni(OH)2 are produced from the reaction of 34.0 mL of a 1.70 M NaOH solution and excess NiCl2? Express your answer with the appropriate units. C.) What is the molarity of 30.0 mL of a NiCl2 solution that reacts completely...
1) NaOH(aq) + HCl(aq) - NaCl(aq) + H2O(1) To determine the concentration of a NaOH(aq) solution, a student titrated a 50. mL sample with 0.10 M HCl(aq). The reaction is represented by the equation above. The titration is monitored using a pH meter, and the experimental results are plotted in the graph below. 13. 0S 7.04 Answer Key on School Loop @ P 1.07. 0 25.0 50.0 Volume HCI added (mL) One student titrated the NaOH(aq) with 1.0 M HCl(aq)...
Consider the following reaction. MgCl2(aq)+2NaOH(aq)⟶Mg(OH)2(s)+2NaCl(aq) A 166.0 mL solution of 0.381 M MgCl2 reacts with a 47.33 mL solution of 0.568 M NaOH to produce Mg(OH)2 and NaCl. Identify the limiting reactant. NaOH Mg(OH)2 MgCl2 NaCl Caclulate the mass of Mg(OH)2 that can be produced. The actual mass of Mg(OH)2 isolated was 0.559 g. Calculate the percent yield of Mg(OH)2.
Important Info: Ka reaction: HC2H3O2(aq) + H2O(l) <-->C2H3O2 (aq) +H3O+(aq) HC2H3O(aq) +OH-(aq) -> C2H3O2-(aq) + H2O (l) A 1.0 L buffer solution is 0.280 M in HC2H302 (acetic acid) and 0.320 M in NaC2H302 (sodium acetate). Calculate the pH of the budder and he Ka for HC2H3O2 IS 1.8 X 10-5 Calculate the pH of te solution above after the addition of 0.0400 moles of solid NaOH. Assume no volume change upon the addition of base.
This FRQ is kinda confusing me, could someone help me please :) 127.Hypochlorous acid, HOCI, is a weak acid in water. The K, expression for HOCI is shown above Write a chemical equation showing how HOCI behaves as an acid in water a. Calculate the pH ofa 0.175 M solution of HOCI b. Write the net ionic equation for the reaction between the weak acid HOCI(aq) and the strong base NaOH(aq) In an experiment, 20.00 mL of 0.175 M HOCI(aq)...
Sodium reacts with water according to the reaction: 2Na(s)+2H2O(l)→2NaOH(aq)+H2(g) Identify the oxidizing agent. a) H2O(l) b) NaOH(aq) c) Na(s) d) H2 (g)
Consider the following reaction. NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l) If 25.0 mL of a 0.100 M solution of NaOH reacted with excess HCl, how many moles of NaCl could form? a. 0.00250 mol b. 0.100 mol c. 25.0 mol d. 2.50 mol 1 points QUESTION 9 Consider the following reaction. How many grams of sucrose would produce 2546 kcal? a. 649.4 g b. 1342 g c. 180.4 g d. 1.897 g
4. Using the following reaction, H2SO4 (aq) + 2 NaOH (aq) → Na2SO4 (aq) + 2 H2O () calculate the molarity of the H2SO4 solution if 17.45 mL of NaOH was necessary to reach the endpoint of a titration. The molarity of the NaOH solution was 0.425 M and 26.30 mL of H2SO4 was added to the Erlenmeyer flask.