Question

I 2) A uniform solid ball has a mass of 20 g and a radius of 5 cm. It rests on a horizontal surface. A sharp force is applied
I have done on three different ways. Someone tell can which one is Correct?
2 m=20g R=5 cm nem FO = 40000N t = 2 x 10 9 sec Average force f = Fo 2 2) а Ft =mo / Fot 2 m v 40, ovo x 2 x 10-4 2x: 208103
(b we know (F) at - ( 4 mR & mR 2) w ce 5 Foxt 14m R2 X 2X10 5% 40,0vo X9X10 15 x 10 14x20 x 10 .: W 5142 8 6 rad I see
Vem - Rw (5x10 2 X 514 9.851) Vem 257. 1486 m 5 d Шк a reg t- Vem a I vem ug 200 6.5 X 9,81 = t- 40.775 sec
a . Given 2og 20 x 10 3 kg 2x 10-2 kg Radius (R) = 5em = 5x10-2m Impulse P = Fot = (40000 x 10-4). 1 AN 4 4. n -2 2x10 = Qoom
b h = gor F h R. - 4 cm = 4x10 cm Then hn v = I wo - har Wo 5X 4 Xlo 2. X 200 2R² x200 20x 16 2x25810-9 8 x 10 sro sadisec
① After rolling , W = R alo R 2 8x 10 x 5x10 4 x 10 2 m/s d we knoul IL t Now, = ffriction XR falling 25x2x10²4101 UN
Now i Ffriction 1 a 5 nr 0.1 X 2x10-2 5 -2 X5X10 250 we know, will be wo wo tat Since, final velocity W=0 aero So wo 8 x 10 3
f at a @ F xot m (vf - Vij 9€ command 40000 x 2 x 10 - 20x10 2x10 3 20 = vf vf 100 m3 (b 2. ott - OL 40,000 X 0.5 x 10-4 (wy
wf 4000 read I see V fo - Loo + 0.4 X20X1080,8 20X10 f- ll mg Also, -2 umg x 5 8 10 - IL こ 245 rad I see wfo 4000 245t Also W
Toot 3.92 X 6118 t = 6.184 second mand © C V Fo ufo = 124 .24 mg This is when ball starts rolle rolling
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Answer #1

d=4cm = 4x102m latt Ed Torque 11 I sou Ed = At de = ar dat I CENE - Wi) 4x10 4 X 4X102 x 4x102 x 10-4 Ik wf 16 x 10-2 z 16 8

For part d the answer is t= 6.184 sec
Same as the third way done by you

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