Question

2. The absorbance of a 2.31 x 10 a wavelength of 266 nm in a 1.00 cm cell. absorptivity at 266 nm. M solution of a compound is 0.822 at Calculate the molar The following absorption data were calculated in-an experiment: 3. Absorbance 0.000 0.090 0.181 0.271 0.361 0.450 0.539 0.627 0.7 Concentration (м) 0.000 1x10-3 2x10-3 3x10 3 4x10-3 5x10~3 6x10-3 7x10-3 8x1 Plot Absorbance vs. Concentration and calculate the molar absorptivity coefficient from the slope if the a) pathlength is 1 cm. b) calculate the concentration (in moles/ absorbance is 0.500. of a solution whose If the solute has a m.w. c) 200, calcualte the amount of solute in 10 ml of'a 0.1M solution d) Calculate the 8 of the solution in part (c) if d- 1.05 g/ml Convert the following values of % T to absorbance 4. b) 80 d) 10 e) 1.0 c) 50 a) 98

Answer 1

2) Molar absorptivity = A/cl

Where A is absorbance = 0.822

c is concentration = 2.31×10^-5 M

l is the path length = 1

Thus, molar absorptivity = 0.822/2.31×10^-5×1

= 3.56×10⁴ M^{​​​​​​-1}​​​​cm^-1