Question

Table 1. Concentrations of [Fe(Phen),1?, M, in water and UV- vis absorbance values recorded at 2 -505 nm. Concentration of [Fe(Phen)/, M Absorbance 9.500 x 10 0.999 4.250 x 10 0.480 0.219 2.125 10% 1.063 x 10 0.104 0.000 0.003 Table 2. UV-vis absorbance values of [Fe(phen)]* held at 35 °C after mixing with H SO, and recorded at 5 minute intervals (in water at max = 505 nm). Time (minutes) Absorbance 0.997 0.935 0.877 0.823 0.772 0.724 0.680 0.638 0.599 0.562 0.527 Table 3. UV-vis absorbance values of [Fe(Phen)held at 45 °C after mixing with H SO, and recorded at 5 minute intervals (in water at max = 505 nm). Time (minutes) Absorbance 0.981 0.615 0.387 0.244 0.156 0.100

Answer 1

1.2 Plot 1: Determination of Extinction Coefficeint 0.8 0.6 0.4 y= 10590x + 0.002 R? = 0.998 0.2 0 0.00001 0.00002 0.00003 0.00004 0.00005 0.00006 0.00007 0.00008 0.00009 0.0001

25000 Plot 2a: Cvst (min) Plot2b: 1/C vs t (min) 20000 15000 0.0001 0.00009 0.00008 0.00007 0.00006 0.00005 0.00004 0.00003 0.00002 0.00001 y=-9E-07x + 9E-05 R = 0.991 10000 y=188.3x+10204 R=0.992 5000 . 10 20 30 40 50 20 30 40 50 60 20 5060 -9.3 -9.4 Plot 2c: In(C) vs t (min) -95 -9.6 -9.71 -9.8 y= -0.012x-9.271 R2 = 1 -10 O

0.0001 120000 Plot 3a: Cvs t(min) Plot 3b: 1/C vs t (min) 0.00008 100000 0.00006 80000 60000 0.00004 40000 0.00002 y=3677.X-540.8 R=0.912 y=-3E-06X+8E-05 R=0.900 20000 152025 30 5 10 15 20 25 30 -0.00002 -20000 WE 0 15 20 25 30 Plot 3c: In(C) vs t(min) 7 9 y=-0.091x-9.296 R? - 0.999

As bointed out from the Absonhance y concentration Hence, & 10590 M 1 cm t question, first job is to determine e to blot from the plot 1; slope: 10590 o This shall be utilized from to cal to calware concentration values " A I c (M) 1 15 At ssc we tabulate the data. tim (M-) en e 0.997 a. u1x 10-510621-87 - 9.27 0.935 8.83x105 | 1132602 -4.33 10 0.897 18.28 x 10-5 112675-26 -9.39 0.823 17.79810-5 11286 7.56 -9.46 20 0.972 AS 1391962 - 9-52 25 16.8uxlas 1146 27.07 9.59 35 10 680 To uexios 10557353 -9.65 90 10.638 5 65 X 165 176 19.49 -4.72 10.5.99 15.31x10.5 (18843-42 | -9 78 To 562 50 4. 98x10 5/20094-88 1-9.8 0.5291 10.72 u 30 16.8ux 10 from plot 2: we find that en c ust plot shows a R² value of 1, which is proof of the perfect linearity. Hence, at 35, it is 1st order "At us, we tabulate the data 7 (min) LA 0.491 ICOM) 1 / (N-1) I enc 19.26410-510795.11 - 9.29 5.81 x 10-517219.51 € 9.75 3.65X1D-527364.34 - 10.12 [2.30x10-5 | 43 401.64 1-10.68 1.unxio-S 167 884 62 -11.12 la uniors 1105900 -11.57 0.387 0.244 0.156 10.100 15 20 25 Ist Ordu from blot 3 we find that an cust plot shows R² vow closest to I (R²0-999). Henu, at use it is ist 1 Thus the order of reaction is 1. wint (Felphens 2 Hope it is helpful.