Molar absorptivity, =
7.0x103 L/(mol.cm)
Percent transmmittance = 65.9 %
Path length = 1 cm
We have:
Absorbance, A = 2 - log (%T)
= 2 - log (65.9)
= 2 - 1.818
= 0.182
From Beer's law:
A = c**l
0.182 = c * 7.0x103 * 1
c = 0.026x10-3
c = 2.6x10-5 Mol/L
Hence, concentration = 2.6x10-5 Mol/L
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