Homework Answers
|
wave number (cm-1) |
A |
B |
unknown |
|
3030 |
0.456 |
0.0315 |
0.434 |
|
2976 |
0.119 |
0.377 |
0.339 |
Absorbance = A = E x b x C
|
wave number |
A |
B |
|
3030 |
E = 45.6 M-cm-1 |
3.15 M-1 cm-1 |
|
2976 |
E = 11.9 M-1 cm-1 |
37.7 M-1 cm-1 |
0.434 = 45.6 A + 3.15 B ----------------------(1)
0.339 = 11.9 A + 37.7 B ---------------------(2)
by solving these two
A = 0.00909 M
B = 0.00612 M
Add Answer to:
Please show work! A solution containing a mixture of the compounds X and Y had an absorbance of 1.06 at 443 nm and...
100 The IR (infrared) spectra of two pure compounds 90 (0.020 M compound A in solvent...
100 The IR (infrared) spectra of two pure compounds 90 (0.020 M compound A in solvent and 0.020 M compound B 80 in solvent) are given. The pathlength of the cell is 1.00 cm. 970 The y-axis in the spectra is transmittance rather than 60 50 absorption, so that the wavenumbers at which there is a dip 40 in the curve correspond to absorption peaks 2976 cm 30 3030 cm Pure A A mixture of A and B in unknown...
A solution containing a mixture of the compounds X and Y had an absorbance of 0.885...
A solution containing a mixture of the compounds X and Y had an absorbance of 0.885 at 443 nm and arn absorbance of 0.760 at 520 nm when measured with a 1.00 cm cell. The molar absorptivities (e)of X and Y at each wavelength are shown in the table below. Wavelength Molar Absorptivity (E, Mcm) A, nm 443 520 16910 3989 4114 6619 What are the concentrations of X and Y in this mixture? Number Number
A solution containing a mixture of the compounds X and Y had an absorbance of 0.729...
A solution containing a mixture of the compounds X and Y had an absorbance of 0.729 at 443 nm and an absorbance of 0.626 at 520 nm when measured with a 1.00 cm cell. The molar absorptivities (elementof) of X and Y at each wavelength are shown in the table below. What are the concentrations of X and Y in this mixture?
K Question 3 of 5 > 10 The IR (infrared) spectra of two pure compounds (0.020 M compound A in sol...
K Question 3 of 5 > 10 The IR (infrared) spectra of two pure compounds (0.020 M compound A in solvent and 0.020 M compound B in solvent) are given. The pathlength of the cell is 1.00 cm. The y-axis in the spectra is transmittance rather than absorption, so that the wavenumbers at which there is a dip in the curve correspond to absorption peaks. A mixture of A and B in unknown concentrations gave a percent transmittance of 52.7%...
A solution containing a mixture of the compounds X and Y had an absorbance of 0.906...
A solution containing a mixture of the compounds X and Y had an absorbance of 0.906 at 443 nm and an absorbance of 0.778 at 520 nm when measured with a 1.00 cm cell. The molar absorptivities (ε) of X and Y at each wavelength are shown in the table below. wavelength Molar Absorptivity (E M^-1cm^-1) Lambda,nm X Y 443 1.600x10^4 3775 520 3893 6264 What are the Concentration of X and Y. Thank you!!
Two analytes, X and Y, have overlapping absorbance spectra for 200 nm <^ < 800 nm....
Two analytes, X and Y, have overlapping absorbance spectra for 200 nm <^ < 800 nm. None the less, determine the concentration of each analyte in an unknown mixture, using the information from absorbance measurements at two a’s. For calibration, individual standards of X and Y were analyzed at a concentration of 2.0 x 10-4M. A 1.0 cm pathlength cell was used. The following data were obtained: Sample Absorbance at 22 Absorbance at 2#1 350 nm 650 nm Unknown Mixture...
An aqueous solution contains two absorbing species, X and Y. When a solution of this mixture...
An aqueous solution contains two
absorbing species, X and Y. When a solution of this mixture is put
into a 5.000 cm cell, the total absorbance of a mixture of X and Y
at 300 nm is 0.372, while at 250 nm it is 0.478. The individual
molar absorptivities of X and Y are as listed below. What are the
individual concentrations of X and Y in this mixture?
250 nm
300 nm
eX
4.05 x 104 M-1 cm-1
3.22...
3. Individual spectra of pure compounds A and B were taken using 1.00 x 10M solutions...
3. Individual spectra of pure compounds A and B were taken using 1.00 x 10M solutions of each, using a cell with a 5.00 cm path length. The transmittance data for each solution at two key wavenumbers are as follows: Solution ) % Transmittance at Wavenumber (cm 2022 1993 31.0 79.7 97.4 20.0 Pure A Pure B An unknown mixture of A and B in a 5.00 cm cell gave transmittance values of 50.6% at 2022 cm? and 20.1% at...
An unknown solution containing a mixture of two compounds is being analyzed by UV/visible spectrometry in...
An unknown solution containing a mixture of two compounds is being analyzed by UV/visible spectrometry in order to determine the amounts of compounds A and B in the sample. Both compounds absorb to some extent at 525 and 630 nm. The calibration curve data obtained during the experiment were analyzed using linear regression analysis. The linear equations for each compound at the various wavelengths are provided in the table below. Results of Linear Regression Analysis Pathlength (cm) 525 nm 630...
Please help JUL). 7.5 X6 M (5.00 mL) 7.50 x O M Van have an unknown mixture of two organic compounds, Wrenoflavin an...
Please help
JUL). 7.5 X6 M (5.00 mL) 7.50 x O M Van have an unknown mixture of two organic compounds, Wrenoflavin and Since whose absorbance spectra are shown below. You have a stock solution of known concentration for each compound available. Suggest a way to analyze this mixture to determine the precise concentration of each component. Absorbance Absorbance 500 510 520 530 580 590 600 500 510 540 550 560 570 Wavelength (nm) 520 530 570 580 590 600...
100 The IR (infrared) spectra of two pure compounds 90 (0.020 M compound A in solvent and 0.020 M compound B 80 in solvent) are given. The pathlength of the cell is 1.00 cm. 970 The y-axis in the spectra is transmittance rather than 60 50 absorption, so that the wavenumbers at which there is a dip 40 in the curve correspond to absorption peaks 2976 cm 30 3030 cm Pure A A mixture of A and B in unknown...
A solution containing a mixture of the compounds X and Y had an absorbance of 0.885 at 443 nm and arn absorbance of 0.760 at 520 nm when measured with a 1.00 cm cell. The molar absorptivities (e)of X and Y at each wavelength are shown in the table below. Wavelength Molar Absorptivity (E, Mcm) A, nm 443 520 16910 3989 4114 6619 What are the concentrations of X and Y in this mixture? Number Number
A solution containing a mixture of the compounds X and Y had an absorbance of 0.729 at 443 nm and an absorbance of 0.626 at 520 nm when measured with a 1.00 cm cell. The molar absorptivities (elementof) of X and Y at each wavelength are shown in the table below. What are the concentrations of X and Y in this mixture?
K Question 3 of 5 > 10 The IR (infrared) spectra of two pure compounds (0.020 M compound A in solvent and 0.020 M compound B in solvent) are given. The pathlength of the cell is 1.00 cm. The y-axis in the spectra is transmittance rather than absorption, so that the wavenumbers at which there is a dip in the curve correspond to absorption peaks. A mixture of A and B in unknown concentrations gave a percent transmittance of 52.7%...
Two analytes, X and Y, have overlapping absorbance spectra for 200 nm <^ < 800 nm. None the less, determine the concentration of each analyte in an unknown mixture, using the information from absorbance measurements at two a’s. For calibration, individual standards of X and Y were analyzed at a concentration of 2.0 x 10-4M. A 1.0 cm pathlength cell was used. The following data were obtained: Sample Absorbance at 22 Absorbance at 2#1 350 nm 650 nm Unknown Mixture...
An aqueous solution contains two
absorbing species, X and Y. When a solution of this mixture is put
into a 5.000 cm cell, the total absorbance of a mixture of X and Y
at 300 nm is 0.372, while at 250 nm it is 0.478. The individual
molar absorptivities of X and Y are as listed below. What are the
individual concentrations of X and Y in this mixture?
250 nm
300 nm
eX
4.05 x 104 M-1 cm-1
3.22...
3. Individual spectra of pure compounds A and B were taken using 1.00 x 10M solutions of each, using a cell with a 5.00 cm path length. The transmittance data for each solution at two key wavenumbers are as follows: Solution ) % Transmittance at Wavenumber (cm 2022 1993 31.0 79.7 97.4 20.0 Pure A Pure B An unknown mixture of A and B in a 5.00 cm cell gave transmittance values of 50.6% at 2022 cm? and 20.1% at...
Please help
JUL). 7.5 X6 M (5.00 mL) 7.50 x O M Van have an unknown mixture of two organic compounds, Wrenoflavin and Since whose absorbance spectra are shown below. You have a stock solution of known concentration for each compound available. Suggest a way to analyze this mixture to determine the precise concentration of each component. Absorbance Absorbance 500 510 520 530 580 590 600 500 510 540 550 560 570 Wavelength (nm) 520 530 570 580 590 600...
Most questions answered within 3 hours.
-
) Assume that in the market for widgets, demand is highly
elastic compared to supply. If...
asked 40 seconds from now -
Why is a personal interview the most important step in the sales
selection process? What are...
asked 9 minutes ago -
In Python rOverlap (x1, y1, w1, h1, x2, y2, w2, h2) A rectangle
is axis-aligned if...
asked 9 minutes ago -
If we observe in a protein solution that DNA is causing a
mixture 260/280 ratio ~0.9,...
asked 19 minutes ago -
Explain the steps involved in making cDNA from mRNA, and how you
would create a cDNA...
asked 20 minutes ago -
A beta (β) particle is described by which of the following?
Select the correct answer below:...
asked 23 minutes ago -
A new machine costs $150,000, lasts 10 years, has an annual
O&M cost of $50,000, and...
asked 26 minutes ago -
A newspaper in a large Midwestern city reported that the
National Association of Realtors said that...
asked 27 minutes ago -
1. Develop a use case diagram for the bank case study described
in Chapter 1. 2....
asked 37 minutes ago -
The phylum Protista has often been referred to as a junk drawer
of classification. Explain what...
asked 44 minutes ago -
The average amount of money spent for lunch per person in the
college cafeteria is $7.09...
asked 46 minutes ago -
You follow the lab procedure and at the end of Part 4C, you used
an average...
asked 1 hour ago